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Z
= 0.8309 + j3.9854 ohms
F
=
+
2
2
Z
R
X
=
+
2
. 0
8309
. 3
9854
Z
Z
= 4.071 ohms
F
Through Fault Current =
3
19.05x10
=
=
I
4.68kA
F
4.071
Through fault current = 4.68kA compared to 17.5kA Busbar fault current due to the effect of the line impedance.
19.05kV
©2010 Siemens Protection Devices Limited
2
Zs
17.5kA
7PG21 Solkor Rf Applications Guide
Z
L
4.68kA
Chapter 3 Page 15 of 15
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