Masonry And Factory Built Fireplace Clearances; How To Determine If Alternate; Floor Protection Materials Are Acceptable - Regency Classic I1200S Owners & Installation Manual

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MASONRY AND FACTORY BUILT FIREPLACE CLEARANCES

The minimum required clearances to combustible materials when installed into a masonry or factory built fireplace are listed below.
Unit Adjacent
Side Wall
(to Side)
A
I1200S 15" (381mm)
Side and Top facing is a maximum of 1.5" thick.
Floor protection must non-combustible, insulative
material with an R value of 1.1 or greater.
* If the hearth extension is flush with the floor (F)
it must extend 19.5" in front of the body face
(E).
Note: Hearth Extension Width (G) is measured
from edge of fuel door to side of hearth.
** A non-combustible mantel may be installed
at a lower height if the framing is made of
metal studs covered with a non-combustible
board.
*** Mantel depth, maximum of 10" (254mm).
Thermal floor protection is not required if the unit is
raised 3.5" minimum (measured from the bottom of
the stove). However, standard ember floor protection
is required. It will need to be a non-combustible mate-
rial that covers 16" (406 mm) in the US and 18" (450
mm) in Canada to the front of the unit and 8" (200
mm) to the sides.
If the unit is not raised, thermal floor protection required
is 18" (450 mm) in the US and Canada.

FLOOR PROTECTION MATERIALS ARE ACCEPTABLE

The specified floor protector should be 3/8"
(18mm) thick material with a K - factor of
0.84.
The proposed alternative is 4" (100mm) brick
with a C-factor of 1.25 over 1/8" (3mm) mineral
board with a K-factor of 0.29.
Step (a):
Use formula above to convert specification
to R-value.
R = 1/k x T = 1/0.84 x .75 = 0.893.
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I1200 Regency Wood Insert
Mantle ** Top
(to Top) Facing
(to Top of Unit)
B C
20" (508mm) 14" (356mm)
Please check to ensure that your floor protection and hearth will meet the standards for
clearance to combustibles. Your hearth extension must be made from a non-combustible
material.

HOW TO DETERMINE IF ALTERNATE

Step (b):
Calculate R of proposed system.
4" brick of C = 1.25, therefore
Rbrick = 1/C = 1/1.25 = 0.80
1/8" mineral board of k = 0.29, therefore
Rmin.bd. = 1/0.29 x 0.125 = 0.431
Total R = Rbrick + Rmineral board =
0.8 + 0.431 = 1.231.
Step (c):
Compare proposed system R of 1.231 to
specified R of 0.893. Since proposed system
R is greater than required, the system is
acceptable.
Side Minimum
Facing Hearth
(to Side of Unit) Extension*
D E
7-3/8"(187mm) 16" (406mm)
H
Clearance diagram for installations
Floor Protection
Minimum Minimum
Hearth Hearth Side
Thickness Extension*
F G
1.5" (38mm) 8" (203mm)
DEFINITIONS
Thermal Conductance:
C = Btu
(hr)(ft )( F)
2 o
Thermal Conductivity:
k = (Btu)(inch) = W
(hr)(ft )( F) (m)(K)
3 o
Thermal Resistance:
R = (ft )(hr)( F) = (m
2 o
Btu W
From Top of
Unit
H
18-3/4"(476mm)
= W
(m )(K)
2)
= Btu
(hr)(ft)( F)
o
)(K)
2