Texas Instruments TI-89 Manual Book page 491

nPr()
MATH/Probability menu
nPr(expression1, expression2)
For integer
expression1
number of permutations of
taken
expression2
can be integers or symbolic expressions.
nPr(expression, 0)
nPr(expression, negInteger)
1/((expression+1) ø (expression+2)...
(expression ì negInteger))
nPr(expression, posInteger)
expression ø (expressionì 1)...
(expression ì posInteger+1)
nPr(expression, nonInteger)
(expression ì nonInteger)!
nPr(list1, list2)
Returns a list of permutations based on the
corresponding element pairs in the two lists.
The arguments must be the same size list.
nPr(matrix1, matrix2)
Returns a matrix of permutations based on
the corresponding element pairs in the two
matrices. The arguments must be the same
size matrix.
nSolve()
MATH/Algebra menu
nSolve(equation, varOrGuess)
error_string
Iteratively searches for one approximate real
numeric solution to
variable. Specify
variable
– or –
=
variable
For example,
nSolve()
, particularly if the "|" operator is used
zeros()
to constrain the search to a small interval
containing exactly one simple solution.
nSolve()
point where the residual is zero or two
relatively close points where the residual has
opposite signs and the magnitude of the
residual is not excessive. If it cannot achieve
this using a modest number of sample points,
it returns the string "
If you use
getType()
using it in an algebraic expression.
Note: See also
zeros() .
474 Appendix A: Functions and Instructions
expression
and
expression1 expression2
‚ ‚ 0,
expression2 nPr()
expression1
at a time. Both arguments
1
expression!/
list
matrix
number or
for its one
equation
as:
varOrGuess
real number
is valid and so is
x x=3
is often much faster than
attempts to determine either one
no solution found
nSolve() in a program, you can use
to check for a numeric result before
, ,
cSolve() cZeros()
nPr(z,3) ¸
with
ans(1)|z=5 ¸
is the
things
nPr(z,ë 3) ¸
nPr(z,c) ¸
ans(1)ù nPr(zì c,ë c) ¸
nPr({5,4,3},{2,4,2}) ¸
nPr([6,5;4,3],[2,2;2,2]) ¸
nSolve(x^2+5xì 25=9,x) ¸
nSolve(x^2=4,x=ë 1) ¸
nSolve(x^2=4,x=1) ¸
Note: If there are multiple solutions, you
can use a guess to help find a particular
solution.
.
nSolve(x^2+5xì 25=9,x)|x<0 ¸
solve() or
nSolve(((1+r)^24ì 1)/r=26,r)|r>
0 and r<.25 ¸
nSolve(x^2=ë 1,x) ¸
."
, and
solve()
zø (zì 2)ø (zì 1)
60
1
(z+1)ø (z+2)ø (z+3)
z!
(zì c)!
{20 24 6}
30 20
[
12 6
3.844...
ë 2.
2.
ë 8.844...
.0068...
"no solution found"
1
]