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Example 3: Displaying harmonics
M A I N
M E N U
M e t e r i n g
D i a g n o s t i c
V i e w
P a r a m e t e r
C h a n g e
P a r a m e t e r
I d e n t i f i c a t i o n
C l e a r
D i s p l a y
S e t u p
Displaying parameters
Example 4: Displaying protection parameter settings
M A I N
M E N U
M e t e r i n g
D i a g n o s t i c
V i e w
P a r a m e t e r
C h a n g e
P a r a m e t e r
I d e n t i f i c a t i o n
C l e a r
D i s p l a y
S e t u p
9 – 47
M E T E R I N G
I
=
7 5 2
a
v
g
U
=
4 0 1
a
v
g
P
= +
2 7 7
k W
S
=
3 0 2
k V A
Q
= +
1 2 0 k V A R
p f
=
0 . 9 1 8
l a g
a
v
g
M W h
W
= + 2 1 2 0 7
f r e q
=
5 0 . 0 2
H z
(8x
)
(8x
M E T E R I N G
U
=
4 0 1
a
v
g
P
= +
2 7 7
k W
S
=
3 0 2
k V A
Q
= +
1 2 0 k V A R
p f
=
0 . 9 1 8
l a g
a
v
g
M W h
W
= + 2 1 2 0 7
f r e q
=
5 0 . 0 2
H z
T e m p
=
4 8 . 0
° C
V I E W
P A R A M E T E R
S y s t e m
C o n f i g .
P r o t .
P a r .
S e t
P r o t .
P a r .
S e t
M e t e r i n g
S e t p o i n t s
C o m m u n i c a t i o n
Language-setting for menu: English (US)
F R E Q U E N C Y
A
f r e q
=
5 0 . 0 2
V
I
=
1 0
T H D
U
=
1 0
T H D
F o r m f a c t o r
=
C r e s t f a c t o r =
)
(5x
)
F R E Q U E N C Y
V
I
=
1 0
T H D
U
=
1 0
T H D
F o r m f a c t o r
=
C r e s t f a c t o r =
H a r m o n i c s
P R O T .
P A R .
S E T
T r i p
=
1 0 0 0
A
S
T r i p
=
8 5 0 0
B
I
T r i p
= 1 4 4 0 0
N
T r i p
=
1 2 0
G
P r o t e c =
5 0 0
T h e r m M e m =
P h a s e S e n =
T a u
=
1 0 0
F R E Q
H z
f
5 0 . 0 2
m i
n
=
2 8 - J A N - 0 1
%
1 6 : 2 9 : 3 2 . 0 1
%
f
5 0 . 0 2
m a
x
=
0 4 - J A N - 0 1
1 . 1
0 8 : 5 9 : 3 8 . 2 1
1 . 4
(5x
)
H A R M O N I C S
I a v g
%
T H D
1 0 . 0 %
2
0 . 0 %
%
3
0 . 0 %
4
0 . 0 %
1 . 1
5
9 . 0 %
1 . 4
6
0 . 0 %
7
3 . 0 %
(28x
)
2 8
0 . 0 %
2 9
0 . 0 %
A
T R I P
A
S t a t u s
=
s
P i c k u p
=
A
D e l a y
=
A
I * t
=
A
o f f
o f f
3ZW1012-0WL11-0HA1
H z
H z
U a v g
1 0 . 0 %
0 . 0 %
0 . 0 %
0 . 0 %
9 . 0 %
0 . 0 %
3 . 0 %
(28x
)
0 . 0 %
0 . 0 %
O n
1 0 0 0
A
4 . 8
s
4
I
t
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