Casio FX-CG10 Software User's Manual page 237

• Graphing is available with Two-Way ANOVA only. V-Window settings are performed
automatically, regardless of Setup screen settings.
• Using the Trace function automatically stores the number of conditions to variable A and the
mean value to variable M, respectively.
k ANOVA (Two-Way)
u Description
The nearby table shows measurement results for a metal product produced by a heat
treatment process based on two treatment levels: time (A) and temperature (B). The
experiments were repeated twice each under identical conditions.
Perform analysis of variance on the following null hypothesis, using a significance level of 5%.
H : No change in strength due to time
o
H : No change in strength due to heat treatment temperature
o
H : No change in strength due to interaction of time and heat treatment temperature
o
u Solution
Use Two-Way ANOVA to test the above hypothesis.
Input the above data as shown below.
List1={1,1,1,1,2,2,2,2}
List2={1,1,2,2,1,1,2,2}
List3={113,116,139,132,133,131,126,122}
Define List 3 (the data for each group) as Dependent. Define List 1 and List 2 (the factor
numbers for each data item in List 3) as Factor A and Factor B respectively.
Executing the test produces the following results.
• Time differential (A) level of significance P = 0.2458019517
The level of significance (
the hypothesis is not rejected.
• Temperature differential (B) level of significance P = 0.04222398836
The level of significance (
hypothesis is rejected.
• Interaction (A
The level of significance (
hypothesis is rejected.
B (Heat Treatment Temperature) B (Heat Treatment Temperature)
A (Time) A (Time)
A1 A1
A2 A2
p
= 0.2458019517) is greater than the significance level (0.05), so
p
= 0.04222398836) is less than the significance level (0.05), so the
B) level of significance P = 2.78169946e-3
p
= 2.78169946e-3) is less than the significance level (0.05), so the
B1 B1
113 , 113 , 116 116 139 , 139 ,
133 , 133 , 131 131 126 , 126 ,
6-44
B2 B2
132 132
122 122