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Calendar Math
Preparation: Press MENU), (Olptions, (Format, (Flix,
before using CalendarMath
Entry-Only Variables:
Calendar:
Setsoneofthree calendars: Enter 1 for actual calendar (with leap
years); 2 for 365-day calendar (no leap years); 3 for 30/360-day
calendar.
Datel:
Sets a beginning date
Solution Variables:
today:
Returns today's date in the current date format.
Datez2:
The destination date a given number of days from Datel
#0fDays: The number of days between two dates.
Equation:
CalendarMath
if(S(today) ,cdate-today,B8x(Datel+Date2
+if(s(Date2) DatecDatel ;#ofDaus)-Date
£:ddayscbatel ;Datez Calendar) —#ofbays)
Example:
What date is 190 days after November 29, 1991?
Highlight CalendarMat hin the Solve catalog and press
(HER=).
Press ves Obptions, (Format, (Flix, g ( 8) to 0 display 6 decimal places.
Type: 1X
,11.291991 [ ¥
, 190 (IIE
Result:
©. 96Ie 9 92 (June 6, 1992)
Press:
Example:
How many days are there between April 6, 1995 and March 11,2003?
Type: 4.861995 EE1XE5, 3.112003 EEIEE
Press: LIANE...
Result:
2,896 .88080808
Example:
What date was 75 days before today's date on a 30/360 calendar?
Type: 3 NEVES, EEE, 50) WELEEN, 75070EEGER
Press: HELGE. ..
Result:
varies depending on today's date
60
2. ANALYZING INFORMATION
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