IBM 7090 Instruction-Reference page 90

SR(9-35)-'
AD 3rd Step L
2.13.21.1
From Fig 5.3-26B
L Time
3rd Step
2.10.43.1
2.10.44.1
t
I~AD(I)
A4(D3)
( For Final Quotient Char Add 200S ; MQ
Overflow or Underflow is Possible)
2.13.27.1
SR (I-S)
~
MQ A6(Dl)
2.13.41.1
SR
(I-S)~
MQ A7(Dl)
2.13.41.1
AD(I-S) ---..
SR A6(Dl)
2.13.04.1
MQ(I-S) ---.
SR A7(Dl)
2.13.12.1
SR (I-S) ---.
AD AS(D3)
2.13.21.1
(Final Quotient Char in SRi
Save Original Divisor Char
in MQ)
FP Shift Lt
A3(Dl) A7(Dl)
A 11 (D1)
2.13.42.1
Sh AC (10-35)
MQ(2-35) Lt
2.12.34.1
2.12.42.1
OBJECTIVES:
1. 27 Reduction Attempts, 26 Shifts
2. Compute Quotient Char
3. Re-compute Original Dividend Char and Set
to AC (Q-S)
4. End Op; Go to I Time
AC(Q-35)---'
AD 3rd Step L
2.13.24.1
,....;....;=..No----<,
6.
~
AD(9-35)~
AC A2(Dl)
A6(Dl) Al0(Dl)
2.13.31.1
,
,
I~MQ(35)
A2(Dl) A6(Dl)
Al0(Dl)
2.09.51.1
(SC = 0) On
~
_loo
I .... AC(35)
A3(Dl) A7(Dl)
Al1(D1)
2.13.42.1
Step SC
A3(D1)A7(DI )
A 11 (D1)
2.13.71.1
Turn Off
9 Ov Tgr
2.10.39.1
l
.
=1
Yes (SR>ACi
Simulated AD
SCarry)
Turn On
9 Ov Tgr
2.10.39.1
,
NOTE: FP Tgr Must be on
to Finish Computation of
Original Dividend Char
,
~----------~~------------~
I
End Op
1
2.10.35.1
1
AD(Q-S)
~
AC Al0(Dl)
2.13.31.1
To I Time Fig S.3-26C
(Original Dividend Char is
now in ACi if Quotient:;> than
1, it is now Original +1)
FIGURE S.3-26C. FDH
+
0240
89
~
fe'
Turn On
FP Tgr
2.10.29.1
I
No