LG Multi V miniARUN Series Installation Manual page 26

Refrigerant Piping
The Amount of Refrigerant
1. Normal condition
The calculation of the additional charge should take into account the length of pipe.
Product Charge(kg)
A
B
Additional charge (kg)
=
Total liquid pipe (m)
Additional refrigerant charge
x
amount per liquid pipe 1m
(Table 1)
+
Correction Factor (kg)
(Table 2)
Total amount(kg)
Table 1
Pipe diameter at
Ø6.35
liquid side (mm)
Additiona
refrigerantl
0.022
amount (kg/m)
2. Special condition
In case of the No. of CST TE/RAC SE/ARTCOOL SF models are over than 50% of the connected indoor units
when the total No. of connected indoor units are over than 50% of the max. connectable indoor units.
Total amount(kg)
I Additional refrigerant charging amount (kg) :
= (A x + B x ß) - (AVG x ß)
• A = Total No. of TE,SE and SF Indoor units,
• B = Total No. of except TE,SE and SF Indoor units,
• AVG = 50% of Max. No. of connectable Indoor units.
Example)
1) Installation Information
- Outdoor unit : 6HP
- Total indoor units : 6 units (TE 3 units, SE 2 units, BH 1 unit)
2) Information from PDB
- Max. No. of connectable indoor units : 10 units
- Calculated additional refrigerant amount = 2 kg :
3) Indoor refrigerant charging amount
= (5 units x 0.5+1 unit x 0.3) - (5 units x 0.3) = 1.3 kg :
Revised the total additional charging amount =
26 Outdoor Unit
= +
A B
Ø9.52 Ø12.7 Ø15.88
0.061 0.118 0.173
= + +
A B C
Example : 5 HP
L2
L1
a
L1 Ø9.52:10m L2 Ø9.52:10m
a Ø9.52:3m b Ø6.35:3m
Additional charge amount R (kg)
= (Lx x 0.022kg/m) + (Ly x 0.061kg/m) + Correction factor
= (12 x 0.022kg/m) + (28 x 0.061kg/m) + 0
= 1.972
Lx : Real total length of liquid pipe Ø6.35(m)
Ly : Real total length of liquid pipe Ø9.52(m)
Table 2
Ø19.05 Ø22.2
PRODUCT CHARGE
0.266 0.354
= 0.5
ß = 0.3
= 2 kg +1.3 kg
= 3.3 kg
L3
b c
L3 Ø9.52:5m
c Ø6.35:4m d
HP
4 5
3.7 3.7
CF
-0.5 0
d
Ø6.35:5m
6
3.7
0