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NORMA 6003/NORMA 6003+/NORMA 6004/NORMA 6004+
Users Manual
How to Make More Accurate Measurements
Measurement Error Caused by the Channel Resistance
By wiring a circuit to match the load, you can minimize the effects of power loss on measurement
accuracy. The wiring of the source and load is discussed in this section.
Figure A1. Connect the Voltage Measurement near the load
Connect the voltage measurement circuit near the load (as shown in
measurement circuit measures the sum of i
current) is the current flowing through the load of the circuit under measurement, and i
is the current flowing through the voltage measurement circuit. Because the current flowing through the
circuit under measurement is i
voltage measurement circuit of the Analyzer is approximately 2 MΩ. If the input voltage is 1000 V, i
approximately 0.5 mA (1000 V/2 MΩ). Only when the load current i
the measurement accuracy is 0.1% or less.
Figure A2. Connect the Voltage Measurement near the source
Connect the voltage measurement circuit near the source (as shown in
measurement circuit measures the sum of e
(error voltage) is the voltage drop across the current measurement circuit. The input resistance of the
current measurement circuit of the Analyzer, I Rin is approximately 0.025 Ω. If the input current is 10 A,
the effect of e
on the measurement accuracy is approximately 0.25 V (10 A×0.025 Ω). Only when the
I
80
I Rin=0.025Ω
+
Source
Connect the Voltage Measurement near the loadL
, only i
reduces measurement accuracy. The input resistance of the
L
V
+
e
e
+
Source
L
i
iv+iL
U Rin=2MΩ
I Rin=0.025Ω
e
i
U Rin=2MΩ
and e
. e
(desired voltage) is the load voltage, and e
L
I
L
iv
iL
Load
Figure
A1). The current
and i
V
V
is 0.5 A or more, the effect of i
L
e
Load
L
Figure
A2). The voltage
. i
(desired
L
(error current)
is
V
on
V
I
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