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12
TOP EXIT - VERTICAL TERMINATION
when (H
) > (V
)
T
T
Simple venting configurations
FIGURE 12
See graph to determine the required vertical rise V
required horizontal run H
MAXIMUM
VERTICAL
RISE
IN
FEET
V
T
HORIZONTAL VENT RUN PLUS OFFSET IN FEET
The shaded area within the lines represents acceptable
values for H
and V
T
T
For vent configurations requiring elbows, the following for-
mulas apply:
Formula 1: H
T
Formula 2: H
+ V
T
90°
V
1
W415-0221 / E / 04.09.02
.
T
.
< 3V
T
< 40 feet
T
90°
H
V
2
H
1
90°
FIGURE 13
Example 5:
V
= 2 ft
1
V
= 1 ft
2
V
= 1.5 ft
3
V
= V
T
H
= 6 ft
1
H
= 2 ft
2
H
= H
R
H
= .03(four 90° elbows - 90°)
O
= .03(90 + 90 + 90 + 90 - 90) = 8.1 ft
H
= H
T
H
+ V
= 16.1 + 4.5 = 20.6 ft
T
T
Formula 1:
Since this formula is not met, this vent configuration is
for the
unacceptable.
T
Formula 2:
Since only formula 2 is met, this vent configuration is unac-
ceptable and a new fireplace location or vent configuration
will need to be established to satisfy both formulas.
H H H H H
T T T T T
Example 6:
V
= 1.5 ft
1
V
= 5 ft
2
V
= V
T
V
H
= 1 ft
3
1
H
= 1 ft
2
2
H
= 1 ft
3
90°
H
= 10.75 ft
4
H
= H
R
H
= .03(four 90° elbows + one 45° elbow - 90°)
O
= .03(90 + 90 + 90 + 90 + 45 - 90) = 9.45 ft
H
= H
T
H
+ V
= 23.2 + 6.5 = 29.7 ft
T
T
Formula 1:
Formula 2:
Since both formulas are met, this vent configuration is ac-
ceptable.
+ V
+ V
= 2 + 1 + 1.5 = 4.5 ft
1
2
3
+ H
= 6 + 2 = 8 ft
1
2
+ H
= 8 + 8.1 = 16.1 ft
R
O
H
< 3V
T
T
3V
= 3 x 4.5 = 13.5 ft
T
16.1 > 13.5
H
+ V
< 40 feet
T
T
20.6 < 40
90°
H
90°
3
H
2
V
H
1
1
+ V
= 1.5 + 5 = 6.5 ft
1
2
+ H
+ H
+ H
= 1 + 1 + 1 + 10.75 = 13.75 ft
1
2
3
4
+ H
= 13.75 + 9.45 = 23.2 ft
R
O
H
< 3V
T
T
3V
= 3 x 6.5 = 19.5 ft
T
19.5 = 19.5
H
+ V
< 40 feet
T
T
29.7 < 40
V
2
45°
90°
H
4
FIGURE 14
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