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46
The Automatic Memory Stack
For
example, you
could
work
the problem
above
by beginning
at
the left
side of
the equation
and simply working through
it
in
left-to-right order.
All
problems
cannot
be
solved
using left-to-
right order,
however,
and
the best
order
for
solving any prob-
lem is to begin
with
the innermost parentheses
and work out-
ward. So, to
solve
the problem
above:
Press
Display
3
3.
~~==:
mmm
3.00
4
i===;:
4.
= ==:
El
0.75
Intermediate
answer for (3
74).
5
5.
~======:
mmm
~
5.
=
00
= ====i
2
2.
El
2.50
B
-1.75
4
4.
~======:
mmm
4.00
3
3.
~1~
2:=;
.
0:=:;:
0==:
10.25
3
I
3.
~:=:==,==:
mmm
I
3.00
.2
13
I
0.213
o
I
0.64
El
I
16.04
5
I
5.
o
~I
=8
' = =
0
=
.2
==
0
==i
Intermediate answer for
(572).
Intermediate
answer for
(3
7
4) - (5
7
2).
Intermediate
answer for (4
x
3)
Intermediate
answer
for
(3
7
4)
-
(5 7 2)
+
(4
x
3).
Intermediate
answer
for
(3
x
.213).
The
first number
is keyed
in.
The final
answer.
Constant Arithmetic
You may have noticed that whenever the
stack
drops
because
of a
two-number
operation (not
because of
mJ
),
the number
in the T-register is reproduced there
.
This
stack operation
can
be
used to insert
a oonstant
into
a
problem
.
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