To Generate A Sequence Of Numbers; To Find The Minimum Value In A List; To Find The Maximum Value In A List - Casio Algebra FX 2.0 PLUS User Manual

u To generate a sequence of numbers
K1(LIST)d(Seq) <expression> , <variable name> , <start value>
, <end value> , <increment> ) w
• The result of this operation is stored in ListAns Memory.
Example To input the number sequence 1
f x
( ) = X
increment of 5
AK1(LIST)d(Seq)vx,
v,b,bb,f)w
Specifying an ending value of 12, 13, 14, or 15 produces the same result as shown above,
because all of them are less than the value produced by the next increment (16).
u To find the minimum value in a list
K1(LIST)e(Min)1(LIST)b(List) <list number 1-20> )w
Example To find the minimum value in List 1 (36, 16, 58, 46, 56)
AK1(LIST)e(Min)
1(LIST)b(List)b)w
u To find the maximum value in a list
Use the same procedure as when finding the minimum value (Min), except press f(Max) in
place of e(Min).
3-2-3
Manipulating List Data
. Use a starting value of 1, an ending value of 11, and an
2
19990401
[OPTN]-[LIST]-[Seq]
2 , 6 2 , 11 2 , into a list, using the function
[OPTN]-[LIST]-[Min]
[OPTN]-[LIST]-[Max]