York PS9 DH Series Installation Manual page 38

High efficiency tubular heat exchanger, single stage downflow/horizontal, 40 - 120 mbh input, 11.72 - 35.17 kw input
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269441-UIM-A-0407
APPLYING FILTER PRESSURE DROP TO
DETERMINE SYSTEM AIRFLOW
To determine the approximate airflow of the unit with a filter in place, fol-
low the steps below:
1.
Select the filter type.
2.
Determine the External System Static Pressure (ESP) without the
filter.
3.
Select a filter pressure drop from the table based upon the number
of return air openings or return air opening size and add to the
ESP from Step 2 to determine the total system static.
4.
If total system static matches a ESP value in the airflow table (i.e.
0.20, 0.60, etc,) the system airflow corresponds to the intersection
of the ESP column and Model/Blower Speed row.
5.
If the total system static falls between ESP values in the table (i.e.
0.58, 0.75, etc.), the static pressure may be rounded to the nearest
value in the table determining the airflow using Step 4 or calculate
the airflow by using the following example.
MODEL NO.
1NP0347
1CT0302
1CT0303
1PS0904
1PS0901
1PS0902
1PS0903
1NK0301
1HT0901
1HT0902
1CB0314
1CB0317
1CB0321
1CB0324
1TK0914
1TK0917
1TK0921
1TK0924
1VK0901
38
FIELD INSTALLED ACCESSORIES - NON-ELECTRICAL
DESCRIPTION
PROPANE (LP) CONVERSION KIT
CONCENTRIC INTAKE/VENT 2"
CONCENTRIC INTAKE/VENT 3"
HIGH ALTITUDE PRESSURE SWITCH KIT
(Does Not Include Orifices)
CONDENSATE NEUTRALIZER KIT
SIDEWALL VENT TERMINATION KIT 3"
SIDEWALL VENT TERMINATION KIT 2"
COMBUSTIBLE FLOOR BASE
These kits are required in downflow application when using G*F*
series coils. These kits are not required with MC/FC series coils,
but please ensure that the coil and furnace are secured and that
there are noair leaks.
COIL TRANSITION KIT
3-WAY TRANSITION KIT
Example: For a 120,000 Btuh furnace operating on high speed blower,
it is found that total system static is 0.58" w.c. To determine the system
airflow, complete the following steps:
1.
Obtain the airflow values at 0.50" & 0.60" ESP.
Airflow @ 0.50": 2152 CFM
Airflow @ 0.60": 2042 CFM
2.
Subtract the airflow @ 0.50" from the airflow @ 0.60" to obtain air-
flow difference.
2042 - 2152 = -110 CFM
3.
Subtract the total system static from 0.50" and divide this differ-
ence by the difference in ESP values in the table, 0.60" - 0.50", to
obtain a percentage.
(0.58 - 0.50) / (0.60 - 0.50) = 0.8
4.
Multiply percentage by airflow difference to obtain airflow reduc-
tion.
(0.8) x (-110) = -88
5.
Subract airflow reduction value to airflow @ 0.50" to obtain actual
airflow @ 0.58" ESP.
2152 - 88 = 2064
ALL MODELS EXCEPT 120 MBH
USED WITH
ALL MODELS
ALL MODELS
40
60/100/120
80/1200
80/1600
ALL MODELS
ALL MODELS
ALL MODELS
14-1/2" CABINET
17-1/2" CABINET
21" CABINET
24 1/2" CABINET
14-1/2" CABINET
17-1/2" CABINET
21" CABINET
24 1/2" CABINET
All MODELS
Unitary Products Group

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