Napoleon Ascent B42NTR Installation And Operation Manual page 90
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exigences d'évacuation
FR
Configuration d'évacuation simple
(deux coudes de 90° seulement)
Lorsque la configuration de l'évacuation exige plus qu'un coude de 90°, les formules suivantes
s'appliquent :
Formule 1 : H
< 3,5V
T
Formule 2 : H
+ V
T
T
Exemple :
V
= 4 PI (1,2m)
1
V
= 1,5 PI (0,5m)
2
V
= V
+ V
= 4PI (1,2m) + 1,5PI (0,5m) = 5,5 PI (1,7m)
T
1
2
H
= 2 PI (0,6m)
1
H
= 1 PI (0,3m)
2
H
= 1 PI (0,3m)
3
H
= 1,5 PI (0,5m)
4
H
= H
+ H
+ H
+ H
R
1
2
3
H
= 0,03 (quatre coudes 90° + un coude 45° - 90°)
O
= 0,03 (90 + 90 + 90 + 90 + 45 - 90) = 9,45 PI (2,9m)
H
= H
+ H
= 5,5PI (1,7m) + 9,45PI (2,9m) = 14,95PI (4,6m)
T
R
O
H
+ V
= 14,95PI (4,6m) + 5,5PI (1,7m) = 20,45PI (6,2m)
T
T
Formule 1 :
H
T
14,95 PI (4,6m) < 19,25 PI (5,9m)
Formule 2 :
H
T
20,45 PI (6,2m) < 24,75 PI (7,5m)
Puisque les deux formules sont respectées, cette configuration d'évacuation est acceptable.
90
W415-1293 / G / 07.06.18
VERTICALE
(MÈTRES) V
T
< 24,75 pieds (7,5m)
= 2PI(0,6m) + 1PI(0,3m) + 1PI(0,3m) + 1,5PI(0,5m) = 5,5PI(1,7m)
4
< 3,5V
T
3,5V
= 3,5PI (1,1m) x 5,5PI (1,7m) = 19,25PI (5,9m)
T
+ V
< 24,75 PI (7,5m)
T
(H
) > (V
)
T
T
Consultez le graphique pour déterminer la course verticale
nécessaire V
par rapport à la course horizontale requise H
T
12,5 (3,8)
12,25 (3,7)
150(3810)
147 (3733.8
COURSE
8,3 (2,54)
100 (2540)
REQUISE
EN PIEDS
66
5,5
(1676.4)
(1,68)
T
50 (1270)
4,2 (1,3)
8 (203)
1 (0,3)
0
2.5
(0.8)
0
1
2,5
(0.3)
(0,8)
1
(0,3)
LONGUEUR DES COURSES HORIZONTALES PLUS
LES DÉVIATIONS EN PIEDS (MÈTRES) H
La section ombragée à l'intérieur des lignes représente
des valeurs acceptables pour H
Simple venting configuration
(only one 90° elbow)
5
7.5
10
12.5
15
17.5
(1.5)
(2.3)
(3.1)
(3.8
(4.6)
(5.3)
(only one 90° elbow)
See graph to determine the required vertical rise V
Simple venting configuration
T
40 (12.2)
15
12.5
20 (6.1)
40 (12.2)
20
17.5
T
FEET (METERS) H
VERTICAL
REQUIRED
RISE IN FEET
(METERS)V
T
39 (11.9)
HORIZONTAL VENT RUN PLUS OFFSET IN
(6.1)
REQUIRED
(5.3)
BGD36
30 (9.1)
GD36
10 (3.1)
39 (11.9)
(4.6)
30 (9.1)
(3.8)
(0.8)
10
(1.5)
0
.
T
for the required horizontal run H
T
)
T
) < (V
7.5
(H
2.5
5
(2.3)
(3.1)
= 4.5FT (1.4m) + 5.4FT (1.6m) = 9.9 FT (3m)
+ H
= H
2
T
T
Formula 1:
2
+ V
1
= V
T
V
= 8 FT (2.4m)
T
T
= 3FT (0.9m) + 8FT (2.4m) = 11FT (3.4m)
H
20.9FT (6.4m) < 40 FT (12.2m)
Formula 2:
Formula 1: H
T
V
= 3 FT (0.9m)
= 2.5 FT (0.8m)
T
H
R
2
O
= 2 FT (0.6m)
H
H
+ V
R
= 9.9FT (3m) + 11FT (3.4m) = 20.9FT (6.4m)
= H
H
1
< V
+ H
9.9FT (3m) < 11FT (3.4m)
2
H
= 2.5FT (0.8m) + 2FT (0.6m) = 4.5 FT (1.4m)
+ V
H
< 40 FT (12.2m)
V
Since both formulas are met, this vent configuration is acceptable.
1
< 40 feet (12.2m)
Example 1:
+ V
T
Formula 2: H
T
< V
T
O
T
= .03 (three 90° elbows - 90°) = .03 (270° - 90°) = 5.4 FT (1.6m)
H
1
For vent configurations requiring more than one 90° elbow, the following formulas apply:
T
(3.1)
7.5
(2.3)
5
(0.8)
acceptable values for H
(1.5)
(METERS)V
VERTICAL
RISE IN FEET
20
(6.1)
17.5
(5.3)
10 (3.1)
20 (6.1)
(4.6)
15
(3.8)
T
2.5
1
H
T
FEET (METERS) H
0
2
1
V
90°
V
12.5
90°
The shaded area within the lines represents
T
and V
HORIZONTAL VENT RUN PLUS OFFSET IN
2
T
10
H
90°
16.2B
3.5
5
7,5
10
12,5
15
(1.1)
(1,5)
(2,3)
(3,1)
(3,8)
(4,6)
3,5
(1,1)
et V
T
90°
H
3
V
2
90°
H
2
For vent configurations requiring mo
90°
V
Formula 1: H
1
Formula 2: H
H
Example 1:
1
V
= 3 FT (0.9m)
90°
1
V
= 8 FT (2.4m)
2
V
= V
+ V
T
1
H
= 2.5 FT (0.8m)
1
H
= 2 FT (0.6m)
2
H
= H
+ H
R
1
H
= .03 (three 90° elbows - 90°) = .03
O
H
= H
+ H
T
R
16.3_2C
H
+ V
= 9.9FT (3m) + 11FT (3.4m) =
T
T
Formula 1:
Formula 2:
Since both formulas are met, this vent
.
T
Se
20
(6.1)
19.25
17,5
20
(5.9)
(5,3)
(6,1)
19,25
(5,9)
T
T
< V
T
T
+ V
< 40 feet (12.2m)
T
T
= 3FT (0.9m) + 8FT (2.4m
2
= 2.5FT (0.8m) + 2FT (0.6
2
= 4.5FT (1.4m) + 5.4FT (
O
H
< V
T
T
9.9FT (3m) < 11FT (3
H
+ V
< 40 FT (12
T
T
20.9FT (6.4m) < 40 F
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