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HP 9g Solving Problems Involving Fractions
Example 6: Are the fractions
Solution:
There are several ways of testing whether two fractions are equivalent. We can subtract one from the other
and see if the result is zero, or we can calculate the cross multiplication since if a/b = c/d then ad = bc.
Doing the division is another way. But let your HP 9g do the hard part, and just enter both fractions. Since
the Hp 9g carries out an automatic simplification, if the fractions displayed in the result line are the same
then they are equivalent. Press:
147O489=
539O1793=
Answer:
Since the latter results in 49 163 too, they are equivalent fractions.
Example 7: Convert the mixed number
Solution:
We have seen how improper fractions are automatically converted to mixed numbers when evaluated. But
the opposite is also possible. The
mixed numbers and improper fractions. Press:
2O89O133~o=
Answer:
355 133, i.e.
and very easy to remember because it's made by duplicating the first three odd numbers and inserting a
division sign in the middle
manual!
↔
A
b
d
Note.
and F↔D must be the last functions entered into the entry line, otherwise a syntax error occurs.
c
e
However, chain calculations are always possible using the ANS function. For example:
sin
Example 8: Calculate
Solution:
The calculation in question is: (
placed in the middle of a calculation. We have to split it this way:
H30~z=†+3O4~n=
We now have the mixed number
so as not to be affected by the current angle mode). We can now convert it to an improper fraction by
pressing:
hp calculators
147
539
and
equivalent to each other?
489
1793
89
to an improper fraction.
2
133
b
A
355
. Incidentally, this is a good approximation to π (within 8.47 millionths of one percent)
133
. And it was also the very first example in the HP-35 operating
133
355
3
30 + )
(
º
and express the result as a fraction.
4
sin 30
(
1
in ANS. (The sequence ~z= inserts the symbol º after 30,
1
4
which returns 49 163
↔
d
function (~o ) carries out conversions between
c
e
+ )
A
º
3 4 F↔D)
- 5 -
↔
b
d
. Trouble is that F↔D cannot be
c
e
HP 9g Solving Problems Involving Fractions - Version 1.1
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