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C
o
i l o
U
n
t i
M
o
d
l e
N
2
T
T
Z
0 9
0 3
A
2
T
T
Z
0 9
6 3
A
2
T
T
Z
0 9
8 4
A
2
T
T
Z
0 9
0 6
A
*Table produced Jan. 2003. For the most current information, please refer to specific equipment Product Data.
Example:
Given:
Qty of 2 units in an area surrounded by a fence on two sides and solid walls on the other two sides. Units
are 2TTZ9030A100A's -
Required:
Determine free air opening space required in fence -
Solution:
4075CFM X Qty of 2 = 8150 CFM
8150 CFM / 300 FPM = 27.17 square feet
Round 27.17 to 27 square feet of free air opening in the 2 fence sections surrounding the units.
X
L
1
i 9
O
t u
o d
g n
U
n
s t i
u
m
b
r e
C
F
M
0 1
0 0
A
0 4
5 7
0 1
0 0
A
0 4
5 7
0 1
0 0
A
0 4
5 7
0 1
0 0
A
0 4
5 7
Required Opening = CFM / 300 FPM
r o
U
n
t i
A
f r i
o l
H
U
n
t i
M
o
d
2
T
W
Z
0 9
2
T
W
Z
0 9
2
T
W
Z
0 9
2
T
W
Z
0 9
Pg. 16
w
T
a
b
e l
e
t a
P
u
m
p
U
n
s t i
l e
N
u
m
b
r e
0 3
A
0 1
0 0
A
6 3
A
0 1
0 0
A
8 4
A
0 1
0 0
A
0 6
A
0 1
0 0
A
C
F
M
0 4
5 7
0 4
5 7
0 4
5 7
0 4
5 7
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