IBM System/360 Field Engineering Manual page 16

Operation Mnemonic Op Code Format Operands Description Interruptions Cond Code
Insert Character IC 43 RX Rl, D2(X2, B2) Opr 2's char placed into opr l, 24-31 Adr Unchanged
(High-order bits unchanged)
Insert Storage Key !SK 09 RR Rl,R2 Opr 2, 8-20 fetches sto key byte. Privileged Unchanged
This byte is placed in opr l, 24-27.
Oper
(opr 2, 0-7 and 21-27 ignored, 28-31
Adr
must= 0) Spec
Load
L 58 RX R1,D2(X2,B2)
Load opr 2 into opr 1 Spec Unchanged
Adr
Load LR
18
RR Rl,R2 Opr 2 into opr 1 None Unchanged
Load Address LA 41 RX Rl, D2(X2, B2) Opr 2, 12-31 to opr 1, 8-31. None Unchanged
Opr 1, 0-7 set to zero
(no storage reference made)
Load and Test LTR 12 RR Rl,R2 Opr 2 into opr 1 None 0 Result= 0
(When opr 1
=
opr 2: same as LTDR) 1 Result < 0
2 Result
>
O
Load and Test (Long) LTDR
22
RR
Rl,R2
Opr 2 into opr 1 Spec Result
(FPR) (FPR) 0 Fract = 0
(When opr 1 and opr 2 specify same reg
1
Result < 0
result is test without data transfer. ) 2 Result
> 0
Load and Test (Short) LTER 32 RR Rl,R2 Opr 2 into opr 1 Spec Result
(FPR) (FPR) 0 Fract = 0
(Low-order half of opr 1 unchanged) 1 Result< 0
(When opr 1 = opr 2: same as LTDR) 2 Result > 0
Load Complement LCR
13
RR Rl,R2 2's complement of opr 2 into opr 1 Exp Oflo 0 Result= O
(overflow when max negative number is 1 Result < 0
complemented) 2 Result
>
0
3 Overflow