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Wiring Work (Continued)
Example of Installation
- Total power cable length L = 100(m), Running current of each units 1[A]
- Total 10 indoor units were installed.
ELCB
or MCCB+
ELB
Apply following equation.
Calculation
Installing with 1 sort wire
220[V]
Installing with 2 different sort wire
220[V]
20
10[A]
0[m]
10[m]
Coef×35.6×L
×i
n
k
k
∑ (
1000×A
k
k=1
2.5[mm
]
2.5[mm
2
2
-2.2[V]
-2.0[V]
-(2.2+2.0+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-11.2[V]
4.0[mm
]
4.0[mm
]
2
2
-1.4[V]
-1.2[V]
-(1.4+1.2+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-10.5[V]
9[A]
Indoor unit1
Indoor unit2
20[m]
10% of input
) <
voltage[V]
]
············ 2.5[mm
············ 2.5[mm
1[A]
100[m]
] ············
2
208.8[V](Within 198V~242V)
it's okay.
] ············
2
209.5[V](Within 198V~242V)
it's okay.
Indoor unit10
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