Viessmann Vitosol 100-FM Technical Manual page 121

Information regarding design and operation
25
20
15
10
5
0
Temperature increase with collectors
Non-heated outdoor pool
Typical temperature curve of an outdoor pool (average monthly val-
ues)
Location: Würzburg
Pool surface area: 40 m
2
Depth: 1.5 m
Position: Sheltered and covered at night
The following diagram shows the average temperature increase that
can be achieved with various ratios of absorber area to pool surface
area. This ratio is independent of the collector type used due to the
comparably low collector temperatures and the operating period
(summer).
Note
Heating and maintaining the pool temperature at a higher set tem-
perature using a conventional heating system does not alter this
ratio. However, the pool will be heated up much more quickly.
8
7
6
5
4
3
2
1
0
0 0.2 0.4
Ratio between the absorber area
and the pool surface area
Vitotrans 200, type WTT
Max. connectable absorber area Vitosol
VITOSOL
0.6 0.8 1.0 1.2
Part no.
m 2
(cont.)
Indoor pools
Indoor pools have a higher target temperature than outdoor pools
and are used throughout the year. If, over the course of the year, a
constant pool temperature is required, indoor pools must be heated
in dual mode. To avoid sizing errors, the energy demand of the pool
must be measured. For this, suspend reheating for 48 hours and
determine the temperature at the beginning and end of the test
period. The daily energy demand can therefore be calculated from
the temperature differential and the content of the pool. For new
projects, the heat demand of the swimming pool must be calculated.
On a summer's day (clear skies), a collector system used to heat a
swimming pool in central Europe produces energy of approx.
2
4.5 kWh/m absorber area.
Calculation example for Vitosol 200-FM/-F
Pool surface area:
Average pool depth:
Pool capacity:
Temperature loss over 2 days:
Daily energy demand:
Collector area:
This corresponds to 6 collectors.
For a first approximation (cost estimate), an average temperature
loss of 1 K/day can be used. With an average pool depth of 1.5 m,
an energy demand of approx. 1.74 kWh/(d·m
required to maintain the set temperature. It is therefore sensible to
use an absorber area of approx. 0.4 m
Under the following conditions, never exceed the max. absorber
area stated in the table:
■ Design output of 600 W/m
■ Max. temperature differential between the swimming pool water
(heat exchanger flow) and the solar circuit return 10 K
3003 453 3003 454 3003 455
28 42
2
36 m
1.5 m
54 m 3
2 K
54 m 3 · 1 K · 1.16 (kWh/K · m
62.6 kWh
62.6 kWh : 4.5 kWh/m 2 =
13.9 m 2
2
pool surface area) is
2 2
per m of pool surface area.
2
3003 456 3003 457
70 116
VIESMANN
3 ) =
13
163
121