Alternate Materials Worksheet - Quadra-Fire 820-0721 Owner's Manual

5700 ACT Wood Stove
How to determine if alternate floor protection materials are acceptable:
All floor protection must be non-combustible (i.e., metals, brick, stone, mineral fiber boards, etc.). Any organic materials
(i.e., plastics, wood paper products, etc.) are combustible and must not be used. The floor protection specified includes
some form of thermal designation such as r-value (thermal resistance) or k-factor (thermal conductivity).
PROCEDURE:
1. Convert specification to r-value:
r-value given - no conversion needed.
k-factor is given with a required thickness (T) in inches:
2. Determine the r-value of the proposed alternate floor protector.
i. Use the formula in step (1) to convert values not expressed as "r".
ii. For multiple layers, add r-values of each layer to determine overall r-value.
3. If the overall r-value of the system is greater than the r-value of the specified floor protector, the alternate is acceptable.
EXAMPLE: The specified floor protector should be 3/4 inch thick material with a k-factor of 0.84. The proposed alternate is
4" brick with an r-factor of 0.2 over 1/8" mineral board with a k-factor of 0.29.
Step (a): Use formula above to convert specification to r-value.
Step (b): Calculate r of proposed system.
Step (c): Compare proposed system r total of 1.231 to specified r of 0.893. Since proposed system r total is greater than
required, the system is acceptable.
2 o
(ft )(hr)(
r =
DEFINITIONS
btu
Page 8
FLOOR PROTECTION (Cont'd)

ALTERNATE MATERIALS WORkSHEET

1
r =
k
4" brick of r = 0.2, therefore:
r
brick
F)
btu(in)
k =
= K x 12
2 o
ft (hr)( F)
250-7090e
K-factor is given with a required thickness (T) in inches:
r-factor is given with a required thickness (T) in inches: r = r x T
x T
1
r = x T
k
1/8" mineral board of k = 0.29, therefore:
= 0.2 x 4 = 0.8
r
mineral board
r = r + r = 0.8 + 0.431 = 1.231
total brick mineral board
btu(ft)
2
r = (ft )(hr)(
K =
2 o
ft (hr)( F)
(btu)(in)
r =
1
x 0.75 = 0.893
=
.84
1
= x 0.125 = 0.431
0.29
1
o
F)
=
k
September 1, 2008
R
1
x T
K x 12