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Casio CFX-9800G Owner's Manual page 73

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To calculate the deviation of
the unbiased variance, the
difference between each da-
tum,-and-mean of
data.-
the above e
Determine the- following:
P distribution
Q distribution ~'
R distribution
t distribution
To calculate x and on-1 for
the following data
Class no.
To determine Med, Max and «.;
Min.
Frequency.
(Continuing) (6i1)(Fa] (DEV)
F3)(xon
1)
AES
55
GIF) (x) Bs):
Sale) es |
518
(x=)
» FN(P()0.20) 68
F2)(Q() 0.25068
F3}(R() 30) 69
Fat)
580)
(Fs)(SET) FJ (STO) BM
Ga) GF) (Scl) BES) (CAL)
: ~
EO)
(Med)
© {Clears memory)
1103)(;)
1069 (07)
1306)(;)310(DT)
15063)(;) 24) (DT)
170(F)(DT)FA(DT)
_ 190E)(DT)EN(DT)ER(DT)
F6)(CAL)
G5 (£) 3 (n)
- (IFA (DEV) Fi (x es
F3)(xon—-1)&2)
[Fs] (Max) Be
[F4) (Min) 2
@miEa(PaR)
1.982142857
. 0.57926
0.098706
1.352-03
3.51188458428
110
130
150
170
190
:
7@
137.7142857
18.42898069
138
190
110
Example
Operation
_
Display'.
The table below shows the
Fs}(SET)
(STO) a)
heights of 20 college stu-
F2)(EDIT)F3)(ERS)
(YES)
ve
dents. Determine what per-
:
centage of the students fall
ms
158.5(](D7)
158.5
in the range 160.5 cm to
l e
160.59 (DT)
:
160.5
175.5 cm. Also; in what per- " |
*
a
S
centile do the 175.5 cm tall
163.365(;)2E(DT)
os
163,3
students fall?
167.5@3(;)2Q(DT)
| :
s |
167.5
a
Soon
=
170.23)(;)3G9(DT)
170.2
= a.
one
a
173.303(;)4@(D7)
173.3
2
160.5
1
175.5(3)(;) 2 (DT)
175.5
3
163.3
2
178.6 §3)(;) 29 (DT)
178.6
4
167.5
2
180.4 63)(;)2(DT)
as
180.4
5
170.2
3
ra
186.7F(DT) | oie
186.7
6
173.3
4
ae
2 (POR) Ls
Se
ie
7
175.5
ae:
(Normalized variate tfor 160.5 cm) |
8
178.6
2
Ht() 160.5069);
—1.633855948
9
180.4
2
:
i
(5 — 1.634).
veal 175.5006 | 0.4963343361.
10
186.7
1
9D.
:
\
;
:
(=0.496)
(Percentage of total) ay
:
:
©(P()0.4960)3
| "
:
€0(P( )@)1.6340 jeg
0.638921,
ts
(Percentile) |
(Result: 63.9% overall)
&3)(R( )0.4960) 68
0.30995
'
(Result: 31 percentile)
eFercentage of the Total
_ 71.634
0.495
y
csatke
y +
10096
1684"
Percentile

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