HP RPN SCIENTIFIC WP 34S Owner's Manual page 48

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By knowing these pin diameters are from a Gaussian process, you get the
best estimates for the mean and standard deviation of your batch by pressing
We stored these two values
in preparation for the next
step already.
So based on the ten pin
sample analyzed, you may
expect 0.5% of all pins with
diameters smaller than
and another 0.5% with diameters greater than
 Are you interested in the mean pin diameter of your batch? Do you want to know
the limit below which it will lie with a probability of e.g. 95%?
the applicable sample mean value and the size of its variation. Use them to find
said limit.
Example
applicable, the standard error tells its variation, and Student's t is needed.
Press ...
So the odds are 95% that the mean pin diameter of that batch will be less
than the confidence limit 12.357. But remember there is an inevitable chance
of 100% – 95% = 5% that it will be greater than that.
35
This value of 95% is called the confidence level of this calculation. 99% are frequently applied as well.
36
returns two numbers: x and y . Only x is interesting in this example. Pressing

quickly out of the way. In a program,
WP 34S Owner's Manual



0.005

0.995
(continued): Since it is a Gaussian process, the arithmetic mean is


1


0.95


36



followed by DROP is a better alternative.
12. 3 52 and
0. 0 09 .
0.5%
↕ Norml⁸


↕ Norml⁸
↕ nΣ

↕ SERR

↕ t⁸(p)

Edition 3.1
99%
0.5%
12. 3 30
12. 3 75 .
35
Then determine
10. 0 00
9. 0 00
0. 0 03
1. 8 33
0. 0 05
12. 3 52
12. 3 57
moves y

Page 48 of 211

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