Napoleon GD33NR Installation And Operating Instructions Manual page 14

14
when (H ) > (V )
T T
Simple venting configurations
BGD34 / GD34
See graph to determine the required vertical rise V
required horizontal run H
MAXIMUM
VERTICAL
RISE IN
FEET
V
T
HORIZONTAL VENT RUN PLUS OFFSET IN FEET
The shaded area within the lines represents acceptable
values for H and V .
T T
For vent configurations requiring more than two 90° elbow
(top exit) or one 90° elbow (rear exit), the following formu-
las apply:
Formula 1: H < 3V
T
Formula 2: H + V
T
Example 7:
90°
V
1
W415-0341 / K / 10.05.07
VERTICAL TERMINATION
FIGURE 17
BGD33 / GD33
.
T
T
< 40 feet
T
90°
H
V
2
H 2
1
90°
FIGURE 18
V
= 2 ft
1
V
= 1 ft
2
V
= 1.5 ft
3
V = V
T 1
H
= 6 ft
1
H
= 2 ft
2
H = H + H
R 1
H
= .03(four 90° elbows - 90°)
O
= .03(90 + 90 + 90 + 90 - 90) = 8.1 ft
H = H
T R
H + V
= 16.1 + 4.5 = 20.6 ft
T T
H
Formula 1:
16.1 > 13.5
Since this formula is not met, this vent configuration is unac-
ceptable.
for the
T
H
Formula 2:
20.6 < 40
Since only formula 2 is met, this vent configuration is unac-
ceptable and a new fireplace location or vent configuration
will need to be established to satisfy both formulas.
Example 8:
H H H H H
T T T T T
H
1
V
= 1.5 ft
1
V
= 5 ft
2
V = V
T 1
H
= 1 ft
1
H
= 1 ft
V
2
H
3
= 10.75 ft
3
H = H + H
R 1
H
= .03(three 90° elbows + one 45° elbow - 90°)
90°
O
= .03(90 + 90 + 90 + 45 - 90) = 6.75 ft
H = H
T R
H + V
= 19.5 + 6.5 = 26 ft
T T
H
Formula 1:
19.5 = 19.5
H
Formula 2:
26 < 40
Since both formulas are met, this vent configuration is ac-
ceptable.
+ V + V
= 2 + 1 + 1.5 = 4.5 ft
2 3
= 6 + 2 = 8 ft
2
+ H
= 8 + 8.1 = 16.1 ft
O
< 3V
T T
3V
= 3 x 4.5 = 13.5 ft
T
+ V < 40 feet
T T
90°
H
45°
2
V
H
1
3
90°
FIGURE 19
+ V
= 1.5 + 5 = 6.5 ft
2
+ H
= 1 + 1 + 10.75 = 12.75 ft
2 3
+ H
= 12.75 + 6.75 = 19.5 ft
O
< 3V
T T
3V
= 3 x 6.5 = 19.5 ft
T
+ V < 40 feet
T T
V
2
90°