Don't
necessarily
shy
away
from
this
one
if
electricity
doesn't
happen
to
be
your
bag.
Enough
information
is
given
tq
write the
program,
and
the
principle,
the optimizing of
a
value,
is
applicable to
many
fields
of
endeavor and
is
little
short of
profound.
With
the
values
given
in
the schematic,
design, write
and
run a
program which
will
try
out
values
of load
resistance
ranging
from
1
to
20 ohms,
in
1
ohm
increments,
and
print
the
answers
to
the following:
1.
Value of
Load
Resistance
(from
1
to
20
ohms)
2.
Total
circuit
power
(circuit
current squared, times source
voltage)
I
2
*
10
3.
Power
lost in
source
(circuit
current squared, times source
resistance)
l
1
*
10
4.
Power
delivered to load
(circuit
current squared, times load
resistance)
I
2
*
R
Note:
Circuit
current
is
found by
dividing
source
voltage
(120
volts)
by
total circuit
resistance (load resistance
+
10
ohms
source
resistance).
Everything
follows
Ohms Law
(V
=
I*R)
and Watts
Law
(P
=
I*V)
GOOD
LUCK!!!! Don't
look
at
the
answer
until
you've got
it
whipped.
120
VOLTS
I
MHMMMKHimmHi
59