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3DQDVRQLF
By replacing I
value to the different formula. and as L
2
the following:
V
T
=
CC
0
i
y
2
L
y
V
T
=
CC
0
i
1
2
L
1
V
=
CC
VV
Ct
2
=
VV
V
L
1
CC
• From t
to t
4
7
At t
, the beam is now positioned at the felt-hand side of the screen. The deflection current i
4
inverted compared to i
negative but this is not possible because of the diode D. C
diode D which are in a conductive state The circuit in figure 5-29 can be represented by a simplified
diagram shown on fig 5-35, 5-36 and 5-37. The corresponding simplified circuit is the same as the one
related to the period t
l
Therefore the deflection current i
i +i
1
y
T
r
D
i
y
Fig. 23: between t
and t
4
Explanation of these diagrams
Between t
to t
, C
continues charging and the current flows through the diode D which is conducting.
4
5
s
At t
, Tr transistor starts conducting. At t
5
reversed biased and stops conducting
cosΩ
t
+
cosΩ
t I
1
Ω
Ω
T
sin
t
0
−
V
Ct
at t
. The voltage in the capacitor C
y
2
to t
.
2
has the same formula: i
y
V
V
Ly
L1
T
r
D
i
1
V
V
Cs
CC
Fig. 24: between t
5
, C
6
>> 1/ (C
y
S
( I
= constant )
1
would have a tendency to become
T
keeps discharging due to transistor Tr or
T
sinwt with ω=1/(√L
=I
y
0
i +i
1
y
V
V
Ly
L1
i
i
1
y
V
V
Cs
CC
and t
Fig. 25: between t
5
6
is fully charged and starts discharging. The diode D is
S
28
) final results between t
L
Ω =
y
C L L
T
C
)
y
S
i +i
1
y
V
T
Ly
r
i
y
V
Cs
and t
6
7
and t
are
2
4
+
L
1
Y
1
is
y
V
L1
i
1
V
CC
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