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General purpose input/output connection
Wire the plug by the provided diagram.
Negative Terminal (–)
5
Each negative terminal is coupled with positive terminal
above it.
Positive Terminal (+)
6
General input output pins that are electrically isolated via
optocoupler.
Phoenix Contact 2x3 plug
Wire the plug by the provided diagram.
RS232 transceiver - top
7
Wire the plug by the provided diagram.
XLR3 for DMX 512 - bottom
8
DMX512 is intended for use with 3 pin XLR connection
capable devices, on which
DMX+ and DMX- are often swapped. The most commonly
encountered pinout is given below.
1 - Ground
2 - Data 1- (Primary Data Link)
3 - Data 1+ (Primary Data Link)
"
check your equipment's product documentation,
electrical schematics and wiring diagram for
exact wiring procedures.
TOP - RS232 transceiver
(Tx) and (Rx) transmit and receive terminal
(G) ground
BOTTOM
(+) and (–) positive and negative terminal of
the DMX512.
(G) ground
14
Positive Terminal (+)
Negative Terminal (–)
"
Copyright © GiVa Audiovisual Technologies BVBA
Infrared connection
9
Wire the plug by the provided diagram.
Wire the anode (+) of the LED facing the
positive terminal of the connector and cathode
(–) facing the negative.
Infrared connection
If you intend to use a LED diode, as a transmitter, make
sure to have a resistor connected in series to limit the cur-
rent through the LED, otherwise it will burn out.
"
read the component's datasheet in order to
gain knowledge of the typical forward voltage.
The resistor value, R is given by:
R = (V
s
R = resistor value in ohms (Ω)
V
= supply voltage
s
V
= LED typical forward voltage
f
I = LED current in amps (A)
"
read the component's datasheet in order to
gain knowledge of the required values.
The LED current must be less than the maximum permitted
for your LED.
If the calculated value is not available choose the nearest
standard resistor value which is greater, so that the current
will be a little less than you chose.
For example
If the supply voltage V
= 5V, and you have an infrared LED
s
(usually V
= 1.5V), requiring a current I = 40mA = 0.040A,
f
R = (5V – 1.5V) / 0.04A = 87,5Ω, so choose 91Ω (the
nearest standard value which is greater).
Wiring the unit
"
- V
) / I
f
"
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