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STEP
1
2
3
4
5
6
7
8
9
10
11
12
13
THE KEYBOARD
ARITHMETIC KEYS
Th s
'program'
can
be
shortened,
without
chang1ng the procedure, by several steps:
1)
the CLEAR key
is, in most cases, an un-
necessa ry step;
2)
step 6 is unnecessary if step 8 is changed
to
t:
STEP
KEY
X
y
z
5
X
4 12
0
6
7
8
8
12
0
8
t
8
8
12
9
9
9
8
12
the contents of the registers is the same, in
both
cases,
at step 9 and one step has been
saved. Similarly, step
13
can be deleted and
step
15
changed to
t.
Method II. -
if the problem is solved by adding (
+
) 8 and
(-
) 9 in the numerator separately
then
more
steps can be saved. This approach changes the
total number of steps from
21
to
16 (17
if
CLEAR has to be used).
(3
X
4)
I
(8 6 9)
=
1.1
(8
X
2)
-
DISPLAY
REGISTERS
KEY
X
y
z
NOT ES
3
3
t
3
3
4
4
3
X
4
12
(3
X
4)
~
Y
8
8 12
+
8 20
(3x4)
+
8~Y
•
9
9
20
-
9
1 1
(3x4)
-t-
(8-
9)
~
Y
8
8
11
t
8
8 1
1
(3x4)
+ (8-
9)
stored in Z
2
2
8
11
X
2
16 1
1
(8x2)
~
Y
6
6
16
11
CONTINUED
35
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