Npr; Npv; Nsolve() - Texas Instruments TI-NSPIRE Reference Manual

nPr()

⇒
Value1 Value2 expression
nPr( , )
For integer Value1 and Value2 with Value1
the number of permutations of Value1 things taken Value2 at a time.
⇒
Value
nPr( , 0) 1
Value negInteger
nPr( , )
⇒
·
Value Value
1/(( +1) (
Value posInteger
nPr( , )
⇒
·
Value Value N
( 1)... (
Value nonInteger
nPr( , )
⇒
Value Value N nonInteger
! / (
⇒
List1 List2 list
nPr( , )
Returns a list of permutations based on the corresponding element
pairs in the two lists. The arguments must be the same size list.
⇒
Matrix1 Matrix2
nPr( , )
Returns a matrix of permutations based on the corresponding
element pairs in the two matrices. The arguments must be the same
size matrix.

npv()

InterestRate CFO CFList
npv( , ,
Financial function that calculates net present value; the sum of the
present values for the cash inflows and outflows. A positive result for
npv indicates a profitable investment.
InterestRate is the rate by which to discount the cash flows (the cost
of money) over one period.
CF0 is the initial cash flow at time 0; it must be a real number.
CFList is a list of cash flow amounts after the initial cash flow CF0.
CFFreq is a list in which each element specifies the frequency of
occurrence for a grouped (consecutive) cash flow amount, which is
the corresponding element of CFList. The default is 1; if you enter
values, they must be positive integers < 10,000.

nSolve()

Equation Var Guess
nSolve( , [=
Equation Var Guess
nSolve( , [=
⇒
number or error_string
Equation Var Guess
nSolve( , [=
⇒
number or error_string
Equation Var Guess
nSolve( , [=
⇒
number or error_string
Iteratively searches for one approximate real numeric solution to
Equation for its one variable. Specify the variable as:
variable
– or –
variable = real number
For example, x is valid and so is x=3.
TI-Nspire™ Reference Guide
‚ Value2 ‚
N
Value negInteger
+2)... ( ))
Value N posInteger
+1)
)!
matrix
CFFreq
[, ])
⇒
number or error_string
])
lowBound
], )
lowBound upBound
], , )
lowBound Var upBound
]) | < <
0, is
nPr()
If there are multiple solutions, you can use a guess to
Note:
help find a particular solution.
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