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10. Installation
Specification of electronic wire
Power supply
Max : 242V / Min : 198V
• Refer to the unit nameplate for rating current.
• Decide the capacity of ELCB(or MCCB+ELB) by below formula.
• Power supply cords of parts of appliances for outdoor use shall not be lighter than polychloroprene sheathed flexible cord. (Code designation
IEC:60245 IEC 57 / CENELEC: H05RN-F or IEC:60245 IEC 66 / CENELEC: H07RN-F )
The capacity of ELCB(or MCCB+ELB) X[A] = 1.25 X 1.1 X ∑Ai
• Decide the power cable specification and maximum length within 10% power drop among indoor units.
n
Coef×35.6×Lk×ik
∑ (
1000×Ak
k=1
Example of Installation
‒ Total power cable length L = 100(m), Running current of each units 1[A]
‒ Total 10 indoor units were installed
10[A]
ELCB
or
MCCB+
ELB
0[m]
• Apply following equation.
n
Coef×35.6×Lk×ik
∑ (
1000×Ak
k=1
• Calculation
– Installing with 1 sort wire
2.5 [mm
2
]
2.5 [mm
-2.2 [V]
-2.0 [V]
220 [V]
-(2.2+2.0+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-11.2 [V]
MCCB
ELB or ELCB
XA, 30 mmA, 0.1 s
XA
) <
10% of input voltage[V]
9[A]
Indoor unit1
10[m]
10% of input
) <
voltage[V]
2
]
······· 2.5 [mm
2
] ·······
Within 198V to
208.8 [V] : it's okay
Power cable
2.5 mm2
‒ X : The capacity of ELCB(or MCCB+ELB).
‒ ∑Ai : Sum of Rating currents of each indoor unit.
‒ Refer to each installation manual about the rating current of indoor unit.
‒ coef: 1.55
‒ Lk: Distance among each indoor unit[m],
Ak: Power cable specification[mm2]
ik: Running current of each unit[A]
Indoor unit2
20[m]
– Installing with 2 different sort wire.
2
4.0 [mm
]
242V
-1.4 [V]
220 [V]
-(1.4+1.2+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-10.5 [V]
Earth cable
Communication cable
2.5 mm2
0.75~1.5 mm2
1[A]
100[m]
4.0 [mm
2
]
······· 2.5 [mm
2
] ·······
-1.2 [V]
209.5 [V] : it's okay
Indoor unit10
Within 198V to
242V
19
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