Angular Mechanics (4, 2); Centripetal Force (4, 3); Hooke's Law (4, 4) - HP 48gII Advanced User's Reference Manual

Angular Mechanics (4, 2)

Equations:
1
- - - I
= I K i =
2
W = K f K i – P =
a t = r
= 2
Example:
Given: I=1750_lb in^2,
Solution: r=1.1017E–3_ft_ lbf, Ki=0_ft lbf, W=6.9221E–3_ft lbf, Kf=6.9221E–3_ft lbf,
at=8.5069E–4_ft/s^2, Ni=0_rpm, f=11.4868_r/min, t=1.0940_min, Nf=1.8282_rpm, Pavg=1.9174E–7_hp.

Centripetal Force (4, 3)

Equations:
2
F = m r
Example:
Given: m=1_kg, r=5_cm, N=2000_Hz.
Solution: =12566.3706_r/s, ar=7895683.5209_m/s, F=7895683.5209_N, v=628.3185_m/s.

Hooke's Law (4, 4)

The force is that exerted by the spring.
Equations:
F = k – x
Example:
Given: k=1725_lbf/in, x=125_in.
Solution: F=-2156.25_lbf, W=-112.3047_ft lbf.
1
2 2
- - - I
i K f = f
2
W
---- -
P a v g =
t
i = 2 Ni
N
=360_°, r=3.5_in, =10.5_r/min^2, i=0_r / s.
2
v v
a r = ---- -
- - -
=
r
r
1 –
2
W = ----- - k x
2
W = r
f = i + t
f = 2 Nf
= 2 N
Equation Reference 5-23