3.3.
SENSITIVITY EQUATION OF THE PERCENT RESTRAINT UNIT
From fig. 4 we may draw out the following equations.
=
−
I
I
I
D
FAULT
X
=
I
*
R
I
*
R
D
E
X
MAX
From (1) and (2) we have:
=
+
I
I
I
( *
R
FAULT
D
D
E
=
+
I
*
1 (
(
R
/
R
D
E
MAX
=
+
I
I
*
1 (
2
( *
R
F
D
E
=
+
=
I
I
I
I
F
FAULT
X
D
We find that the unit will produce an output (operate) when:
−
≥
I
K
*
I
0
1 .
D
F
So:
≥
+
I
K
*
I
*
1 (
2
( *
D
D
−
+
I
*
1 (
K
*
1 (
2
( *
D
In the same way the unit does not operate when:
−
+
I
*
1 (
K
*
1 (
2
( *
D
For more security we can say that the unit will not trip if:
−
+
I
*
1 (
K
*
1 (
2
( *
D
OR
−
+
1
K
*
1 (
2
( *
R
/
R
E
Thus:
<
+
1
K
*
1 (
2
( *
R
/
R
E
<
+
R
K
*
R
2
MAX
MAX
From this we can finally deduce that:
>
* −
R
R
1 (
K
)
2 /
E
MAX
2
*
K
*
R
<
E
R
−
MAX
1
K
GEK-98514B
=
/
R
)
MAX
))
/
R
))
MAX
+
+
*
1 (
(
R
/
R
))
E
MAX
R
/
R
))
E
MAX
≥
R
/
R
)))
0
1 .
E
MAX
<
R
/
R
)))
0
1 .
E
MAX
<
R
/
R
)))
0
E
MAX
<
))
0
MAX
))
MAX
*
K
*
R
E
K
BUS1000 Busbar Protection
I
( *
R
/
R
)
D
E
MAX
3. OPERATION PRINCIPLES
[9]
[10]
[11]
[12]
[13]
[14]
[15]
[16]
[17]
[18]
[19]
[20]
3-5