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Chapter 6: Complex Number Calculations
Example
(12–6i) + (7+15i) –
(11+4i) =
6×(7–9i) ×
(–5+8i) =
16×(sin30°+
icos30°)÷(sin60°+
icos60°)=
r1 = 8, θ1 = 70°
r2 = 12, θ2 = 25°
↓
r = ?, θ = ?°
(1 + i)
↓
r = ?, θ = ?°
2
(2 – 3i)
=
1
=
1 + i
conj(5+2i) =
74
Key operations
b 4
( 12 - 6 Q ) +
( 7 + 15 Q ) -
( 11 + 4 Q ) e
6 k ( 7 - 9 Q )
k ( S 5 + 8 Q
) e
16 k ( v 30 +
Q $ 30 ) z (
v 60 +
Q $ 60 ) e
@ u 8 R 70 + 12
R 25 e
@ E 1 + Q e
@ u
@ E ( 2 - 3 Q
) A e
( 1 + Q ) @
Z e
I 0 ( 5 + 2 Q
) e
Result
COMPLEX MODE
0.
8.
+5.i
222.
+606.i
13.85640646
+8.i
18.5408873
42.76427608
∠
1.
+1.i
1.414213562
45.
∠
–5.
–12.i
0.5
–0.5i
5.
–2.i
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