hp40g+.book Page 27 Friday, December 9, 2005 1:03 AM
Step-by-Step Examples
Solution 1
Start by defining the
1
g x ( )
----------- -
=
2
–
following:
x
+
Now type
PROPFRAC(G(X)). Note
that PROPFRAC can be
found on the POLYNOMIAL
submenu of the MATH
menu.
Pressing
yields the
result shown at the right.
Solution 2
Enter the integral:
2
∫
g x ( ) x d
I
=
.
0
Pressing
yields the
result shown at the right:
Pressing
again
yields:
Working by hand:
(
) 1
2x
+
3
=
2 x
+
2
–
, so:
Then, integrating term by term between 0 and 2
produces:
2
∫
g x ( ) x
[
(
d
=
2x
–
ln
0
ln
4
=
2 2
ln
that is, since
2
∫
g x ( ) x
d
=
4
–
ln
2
0
2
1
g x ( )
----------- -
=
2
–
x
+
2
x
=
2
)
]
x
+
2
x
=
0
:
16-27