hp40g+.book Page 4 Friday, December 9, 2005 1:03 AM
Example 3
16-4
Press
to
evaluate the selection.
It remains to transform
3 12
and combine it
–
6 3
with
. Follow the
same procedure as
undertaken a number of
times above. You will find that
6 3
, and so the final two terms cancel each other
out.
Hence the result is
C
=
4 5
D
Given the expression
•
expand and reduce D
•
factor D
(
•
solve the equation
•
evaluate D for x = 5.
Solution: First, enter D using the Equation Writer:
3
X
1
2
81
Press
to select
2
(
)
3X 1
–
and
to
expand the expression. This
2
9x
–
6x
+
1 81
–
gives:
3 12
is equal to
2
(
)
=
3x 1
–
–
81
:
)
⋅
(
)
3x 10
–
3x
+
8
=
0
and
Step-by-Step Examples