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--- 5 row(s) selected.
Note that the first row retrieved displays null because the offset from the current row does
not fall within the results set.
•
Retrieve the difference between the TS column in the current row and the TS column in the
previous row:
SELECT DIFF1 (TS) AS DIFF1_TS
FROM mining.seqfcn
SEQUENCE BY TS;
DIFF1_TS
--------------------
30002620.000000
134157861.000000
168588029.000000
114055223.000000
--- 5 row(s) selected.
Note that the results are expressed as the number of seconds. For example, the difference
between TIMESTAMP '1951-02-15 14:35:49' and TIMESTAMP '1950-03-05 08:32:09' is
approximately 347 days. The difference between TIMESTAMP '1955-05-18 08:40:10' and
TIMESTAMP '1951-02-15 14:35:49' is approximately 4 years and 3 months, and so on.
•
This query retrieves the difference in consecutive values in I1 divided by the difference in
consecutive values in TS:
SELECT DIFF1 (I1,TS) AS DIFF1_I1TS
FROM mining.seqfcn
SEQUENCE BY TS;
DIFF1_I1TS
-------------------
.0007319
-.0000679
-.0000857
.0000646
--- 5 row(s) selected.
Note that the results are equivalent to the quotient of the results from the two preceding
examples. For example, in the second row of the output of this example, 0.0007319 is equal
to 21959 divided by 30002620.
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DIFF1 Function
335
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