Samsung RVMC060GDM0 Technical Manual page 175

1-4. Example for unit selection with cooling load
(1) Given condition
1) Design condition <Cooling: Indoor 20°C(WB), Outdoor 33°C(DB)>
2) Cooling load
Location
Load (kW)
3) Power supply unit: 3 Phase 380V 50Hz
4) Pipe length: 30m
(2) Indoor unit selection
Select the suitable capacity for condition of 'Indoor 20°C(WB), Outdoor 33°C(DB)' using
indoor unit capacity table. The selected result is as follow.
Location
Load (kW)
Unit size
Capacity(kW)
(3) Outdoor unit selection
1) Assume the indoor unit and outdoor unit combination as follow.
Outdoor unit: RVMH100GAM0
Indoor unit: AVMKH026EA0 x 2,AVMKH035EA0 x 2,AVMCH052EA0 x 1,AVMCH070EA0 x 1
2) Indoor unit combination total capacity index
2.6x2 + 3.5x2 + 5.2x1 + 7.0x1 = 24.4, (24.4/28.0) x 100% = 87%
3) Result: Because it is within 50~130%, it is 'Right' selection (Within 100% for the Middle East).
(4) Real function data with indoor unit combination
1) For the 87% combination, calculate the cooling capacity of outdoor unit (RVMH100GAM0).
27.14kW ← 90% (Indoor temperature: WB 20°C, Outdoor temperature: DB 33°C)
24.12kW ← 80% (Indoor temperature: WB 20°C, Outdoor temperature: DB 33°C)
Therefore, 26.23 = 24.12 + {(27.14-24.12)/10}x7: Calculated in 87%
2) Outdoor unit (RVMH100GAM0) cooling capacity: 26.23kW ← 87%
(Indoor temperature: WB 20°C, Outdoor temperature: DB 33°C)
3) Capacity change factor with pipe length (30m): 0.95(30m) (Refer to page IV-45.)
4) Each cooling capacity
AVMKH026EA0: 26.23 x 26/244 x 0.95 = 2.66(kW)
AVMKH035EA0: 26.23 x 35/244 x 0.95 = 3.57(kW)
AVMCH052EA0: 26.23 x 52/244 x 0.95 = 5.31(kW)
AVMCH070EA0: 26.23 x 70/244 x 0.95 = 7.15(kW)
Location
Load (kW)
Unit size
Capacity(kW)
Room A Room B Room C
2.4 2.6 3.2
Room A Room B Room C
2.4 2.6 3.2
26 26
2.8 2.8 3.77
Room A Room B Room C
2.4 2.6 3.2
26 26
2.66 2.66 3.57
Ι Λ
3
Room D Room E
3.4 4.8
Room D Room E
3.4 4.8
35 35 52
3.77 5.6
Room D Room E
3.4 4.8
35 35 52
3.57 5.31
Room F
7.2
Room F
7.2
70
7.54
Room F
7.1
70
7.15