Fig. 24
[EXAMPLE]
SWEEP TIME/DIV is 0.1 ms and apply 1.75 kHz reference
signal. Adjust the VARIABLE so that the distance of one
cycle is 5 divisions.
Substituting the given value:
Horizontal coefficient =
5 x 0 . 1 (ms)
Then, SWEEP TIME/DIV is 0.2 ms and horizontal amplitude
is 7 divisions. (See Fig. 24)
Substituting the given value:
Pulse width = 7 (div) x 1.142 x 0 . 2 (ms) = 1.6 ms
26
Unknown
signal
= 1.142