Determining The Centre Of Gravity Of The Body And Payload - Iveco DAILY 4x4 Instructions Manual

1-10
GENERAL SPECIFICATIONS
1.13.2

Determining the Centre of Gravity of the Body and Payload

Positioning on the longitudinal plane
To establish the location of the centre of gravity of the body and payload the following examples below may be used as guidelines.
The technical documentation specific to each model (chassis cab drawing) give the positions permitted with the vehicle in its standard
form. The masses and positioning of the single components of the vehicle are given in the chassis and weight distribution diagram.
Figure 1.1
W = Body + payload (kg)
W1 = Body and payload acting on front axle (kg)
W2 = Body and payload acting on rear axle (kg)
L1 = Distance of the centre of gravity from the rear axle centre line (mm)
L = Wheelbase (mm)
Example of calculation of the load barycentre position
Consider a 40C13 vehicle with a wheelbase of 3450 mm with:
1. GWW= 4200 kg (permitted maximum: 1900 kg on the front and 3100 kg on the rear)
2. KERB WEIGHT = 1955 kg (1340 kg on the front axle, 615 kg on the rear)
The permitted maximum load (body + payload) will be W = 4200 - 1955 = 2245 kg. Let us calculate the position of the center
of gravity in which the maximum permitted on the front axle is achieved. Let us assume an uniform distributed load .
In this case, out of 2245 kg. W
kg will affect the rear axle.
Thus, the following will be obtained:
1. W = 560 kg
1
2. L = 3450 mm
3. W = 2245 kg
L = W x L / W = 860 mm
1 1
The center of gravity of the load (Body + payload) must not be more than 860 mm far from the rear axle; otherwise, the front
axle would be overloaded.
Dimensions and masses
Base - May 2007
⋅ L
W
1
=
L
1
W
= 1900 - 1340 = 560 kg will affect the front axle, while the remaining W
1
respectively L1 = L − W2 ⋅ L
W
D 4 4
AILY X
102452
= 2245 - 560 = 1685
2
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