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The Automatic Memory Stack
47
Example:
A
bacteriologist
tests a certain strain whose
popu-
lation typically increases by
15%
each day.
lfhe
starts a sample
culture of
1000,
what will
be the
bacteria population at
the
end
of each
day
for six consecutive
days?
Method:
Put the growth
factor (1.15)
in
the Y-
,
Z-
,
and T-
registers
and
put the
original
population
(1000)
in the X-register.
Thereafter, you get the new population
whenever you
press
0.
Press
Display
1.15
1
1 . 1 5
Growth
factor.
Imim
1
1.15
Imim
1
1.15
Imim
1
1.15
Growth
factor
now
in T.
1000
1
1000.
Starting population.
0
1
1150.00
Population
after
I
st day.
0
1
1322.50
Population
after 2nd day.
0
1
1520.88
Population
after 3rd day.
0
1
174 9.01
Population
after
4th
day.
0
12011.36
Population
after 5th day.
0
1
2313.06
Population
after 6th day.
When
you
press0the first time,
you calculate
1.15
x
1000.
The
result (1150 .00) is displayed in the
X-register and a
new
copy of
the
growth
factor drops into the
Y
-register.
Since a
new copy
of
the
growth
factor is duplicated from
the T-register each
time the
stack
drops
,
you
never have to reenter it.
Notice that performing a two-number
operation such as 0
causes the number in the T-register to
be
duplicated
each
time the
stack
is dropped. However
,
the
mJ
key
,
since
it
rotates
the
contents
of the
stack registers
,
does
not
rCll'ritc
any
number
,
but merely
shifts
the numbers that
are already
in
the
stack.
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