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ESC
&
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LESSON 3
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In this lesson, how to specify descender data is explained.
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Line No.
10-70
Refer to LESSON 1.
80-90
Start of character-defining statements.
140, 200
Since the MSB of the attribute determines whether or not the
descender exists, both "1" and "0" are defined.
If
the MSB of
the attribute is "0", the descender exists and the defined
pattern will be shifted down one dot and printed.
I
«1e,j!1Li
Download Character
LESSON
:~;
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20
See if DIP SW
1-4
is
OFF.
30
Defines a box
40
Copies original character patterns into Download set
50
LPF, I NT CHR$ (27) ; ":
II ;
CHF($ (0) ; CHR$ «(2) ; CHR$ (0) ;
60 ' Selects Download character set
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7(2) LF'R I NT CHR$ (27) ;
II
%
II
~
CI·-IR$ (
1 ) :;
CHR$
(!!j) ;
8(2) . Defines a box pattern
-
<;' ( 2)
LPF~
I r\IT CHR$
(~.?7)
;
II
~<"
;
CHR!t=, (0) ;
100 'Defines two boxes into
@
and A
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1 H:'l L.PFn NT
"1:s!A
II ;
120 'Sends a box pattern
13(2)
'139
has no DESCENDER Attributes
~4(2)
LPRINT CHR$(139);
150 LPRINT
CHR$(255);CHR$«(2);CHR$(129);CHR$(01~CHRS(129);
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160 LPRINT CHR$(0);
170 LPRINT CHR$(129);CHR$«(2);CHRS(129);CHR$«(2);CHRS(255);
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180 'Sends a box oattern
190 '11 has a DESCENDER Attribute
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20(2) LPRINT CHRS(11):;
210 LPRINT CHR$(255';CHR$«(2);CHR$(129);CHRS(0);CHRS(129';
220 LPRINT CHR$«(2):;
230 LF'RINT
CHR$(129);CHRS(0'~CHR$(129);CHRS(0);CHR$(255);
240
'Ok.
Let's draw the box.
2~::.j(~
LPR
I
NT
II
Th
i
'5
i
s;;
,,~.
b m·(
• ...........
-:>
I?,J"
260
L.Ph: 1
Nl' 1'T"h
t~Sf.i)
Cl.I~ E~
b
0)-(
E~':;
•...... -..._ ..
:>
1~{.1I~(.~@
II
27(;~
L.F'FdNT""
T~'>In
o·f t.l'v·?m du I'
!.,;:..v'E)
DESCENDEF~~3."
~.~~
t3
~:)
E r-J D
-
This is a
bo~
---~
0
T h
(=:~
,,;
E'
,!~.
r-
(-'2
b
C);.~ e':::; ..
":.
[rlX1J
Twu of them do have DESCENDERS.
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3-46
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