Solving The Complex Equation Ax = B - HP -15C Owner's Handbook Manual

168 Section 12: Calculating with Matrices
Writing down the elements of C,

C
where the upper half of matrix C is the real part of ZZ
is the imaginary part. Therefore, by inspection of matrix C,
As expected,

Solving the Complex Equation AX = B

You can solve the complex matrix equation AX = B by finding X = A
Do this by calculating X
To solve the equation AX = B, where A, X, and B are complex matrices:
1. Store the elements of A and B in memory, in the form either of Z
C
of Z .
2. Recall the descriptor of the matrix representing B into the display.
3. If the elements of B were entered in the form B
transform B

. 1 0000


 
11

. 4 0000 10



11
. 1 0000 10




11

. 1 0000 10

. 1 0000


1

ZZ



. 4 0000

. 1 0000


i


. 1 0000

- 1
ZZ
P -1
= (Ã)
C P
into B .

 
. 2 8500 10
. 1 0000


. 3 8000 10

 
. 1 0500 10

. 2 8500


11
10 . 1 0000

 11
10 . 3 8000

 
11
10 . 1 0500
   
1 0 0 0

   
i
   
0 1 0 0
P
B .

10

 

P


1
ZZ
,

10


10

-1
and the lower half
 
 10
10



 
 11
10



10


10
C , press ´p to
-1
B.
P
or