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To determine the logical XOR of 1010
A 1010 13(BASE)3(xor) 1100 =
To determine the logical XNOR of 1111
A 1111 13(BASE)4(xnor) 101 =
To determine the bitwise complement of 1010
A13(BASE)5(Not) 1010 )=
To negate (take the two's complement) of 101101
A13(BASE)6(Neg) 101101 )=
Note: In the case of a negative binary, octal or hexadecimal value, the
calculator converts the value to binary, takes the two's complement, and
then converts back to the original number base. For decimal (base-10)
values, the calculator merely adds a minus sign.
Equation Calculations (EQN)
You can use the following procedure in the EQN Mode to solve simultaneous
linear equations with two or three unknowns, quadratic equations, and cubic
equations.
1. Press N5(EQN) to enter the EQN Mode.
2. On the menu that appears, select an equation type.
To select this calculation type:
Simultaneous linear equations with two
unknowns
Simultaneous linear equations with
three unknowns
Quadratic equation
Cubic equation
3. Use the Coefficient Editor that appears to input coefficient values.
x
• To solve 2
the following for the coefficients (
3=.
• To change a coefficient value you already have input, move the cursor
to the appropriate cell, input the new value, and then press =.
• Pressing A will clear all of the coefficients to zero.
Important: The following operations are not supported by the Coefficient
Editor: m, 1m(M–), 1t(STO). Pol, Rec, ÷R, and multi-statements
also cannot be input with the Coefficient Editor.
4. After all the values are the way you want, press =.
• This will display a solution. Each press of = will display another
solution. Pressing = while the final solution is displayed will return to
the Coefficient Editor.
• You can scroll between the solutions using the c and f keys.
• To return to the Coefficient Editor while any solution is displayed, press
A.
Note: • Even if Natural Display is selected, the solutions of simultaneous
linear equations are not displayed using any form that includes ' .
• Values cannot be converted to engineering notation on the solution screen.
– 3 = 0, for example, press 3 in step 2, and then input
x
2
+
and 1100
2
and 101
2
Press this key:
1(a
2(a
3(aX
4(aX
a
b
= 2,
= 1,
E-35
(1010
xor 1100
2
2
0000000000000110
(1111
xnor 101
2
2
1111111111110101
(Not(1010
))
2
2
1111111111110101
(Neg(101101
2
1111111111010011
X + b
Y = c
)
n
n
n
X + b
Y + c
Z = d
n
n
n
2
+ bX + c = 0)
3
2
+ bX
+ cX + d = 0)
c
= –3): 2=1=-
)
2
)
2
))
2
)
n
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