Samsung RHF100KHEA User & Installation Manual page 40

Wiring work
Specification of electric wire
Power supply MCCB
Max : 242V
Min : 198V
Decide the capacity of ELCB(or MCCB+ELB) by below formula.

The capacity of ELCB(or MCCB+ELB) X [A] = 1.25 X 1.1 X ∑Ai
T X : The capacity of ELCB(or MCCB+ELB).
T ∑ Ai : Sum of Rating currents of each indoor unit.
T Refer to each installation manual about the rating current of indoor unit.
ecide the power cable specification and maximum length within
D

10% power drop among indoor units.
n Coef×35.6×L
∑ (
k=1
T coef: 1.55
T Lk: Distance among each indoor unit[m], Ak: Power cable specification[mm
ik: Running current of each unit[A]
Example of Installation
- Total power cable length L = 100(m), Running current of each units 1[A]
- Total 10 indoor units were installed
10[A]
ELCB
or MCCB+
ELB
0[m]
Apply following equatio

n
∑ (
k=1
Calculation

Installing with one size cable.

2.5[mm ]
2
-2.2[V]
220[V]
Installing with two size cables.

4.0[mm ]
2
-1.4[V]
220[V]
40
RHF050KHEA_IB,IM_E_32885-3.indd 40
ELB or ELCB
X A, 30mmA
X A
0.1 sec
×i
k k
) <
10% of input voltage[V]
1000×A
k
9[A]
Indoor unit1
10[m]
n.
Coef×35.6×L ×i
k k
) <
1000×A
k
2.5[mm ]
2
-2.0[V]
-(2.2+2.0+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-11.2[V]
4.0[mm ]
2
-1.2[V]
-(1.4+1.2+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-10.5[V]
Power cable Earth cable
2 2
2.5mm 2.5mm
]
2
Indoor unit2
20[m]
10% of input
voltage[V]
············ 2.5[mm ] ············
2
············ 2.5[mm ] ············
2
Communication cable
2
0.75~1.5mm
 Rating current
Rating
Model
current
RHF050KHEA 1.7A
RHF100KHEA 3.7A
1[A]
Indoor unit10
100[m]
208.8[V](Within 198V~242V)
it's okay
209.5[V](Within 198V~242V)
it's okay
2011-10-12 오후 5:30:36