12 CONTROL SUB FUNCTIONS
(2) When "PLS (pulse)" is set as the control unit
When using PLS (pulse) as the control unit, set the electronic gear as
follows.
AP = "No. of pulses per rotation"
AL = "Movement amount per rotation"
AM = 1
Example) When the motor is the HC-MF (8192PLS/rev)
AP = 8192 ...... Pr.2
AL = 8192 ...... Pr.3
AM = 1 ........... Pr.4
(3) When "degree" is set as the control unit for a rotary axis
When the rotary axis is used, the motor is HC-SF (16384PLS/rev) and the
reduction ratio of the reduction gear is 3/11
First, find how many degrees the load (machine) will travel (
motor turns one revolution (AP).
•
AP(No. of pulses per rotation) = 16384
•
S
(Machine travel value per motor revolution)
Substitute this for the above expression (1).
16384 [PLS]
AP
=
360.00000 [degree] × 3/11
S
16384 [PLS] × 11
=
360.00000 × 3
180224
=
1080.00000
11264
=
67.50000
11264 (AP)
=
0.06750 (AL) × 1000 (AM)
12 - 16
Reduction
ratio 3/11
M
×
= 360.00000 [degree]
×
= 360.00000
3/11
11264 (AP)
=
67.50000(AL) × 1 (AM)
MELSEC-Q
S
) when the
Reduction ratio