Table 4.6 Examples Of Typical Air Conditioner Cooling Capacity Calculations - Fujitsu M10 Series Installation Planning Manual

The values in the table involve certain characteristic curve and air-line diagram read
errors.

Table 4.6 Examples of typical air conditioner cooling capacity calculations (1/2)

Item
Enthalpy of the air at the
conditioner inlet
Enthalpy difference
between the air conditioner
coil inlet and the coil
surface
Enthalpy on the air
conditioner coil surface
Air conditioner bypass
factor
Enthalpy of the air coming
out of the air conditioner
Temperature and humidity
at the inlet
Enthalpy on the air
conditioner coil surface
Temperature and humidity
of the air coming out of the
air conditioner
Air conditioner cooling
capacity
C120-H007-08EN
Calculated value
i =45.4 kJ/kg Determine the enthalpy at 24C (75.2F)and
1
45%RH from the air-line diagram
(19.6 Btu/lb)
i=16.7 kJ/kg
Determine the difference from typical air
(7.2 Btu/lb) conditioner characteristics.
i =28.7 kJ/kg Determine the enthalpy from the air-line
2
diagram.
(12.4 Btu/lb)
BF=0.095 Determine the bypass factor from typical air
conditioner characteristics.
i =30.3 kJ/kg Calculate the enthalpy by solving the bypass
3
factor relation BF= (i
(13.1 Btu/lb)
24C (75.2F) 45% Setup condition
9.7C (49.5F) Determine the temperature and humidity
100% from the point of intersection between the
enthalpy (i
surface and 100% relative humidity in the
air-line diagram.
11.1C (52F) 92% Determine the temperature and humidity
from the point of intersection of a line
segment, between the status point at the
conditioner inlet and that on the air
conditioner coil surface, and the enthalpy of
the air coming out of the air conditioner in
the air-line diagram.
145.6 MJ/h (i
(138,029 Btu/h)
=15.1 (kJ/kg)  135 (m
60 (min/h) / 0.84 (m
=6.5 (Btu/lb)  4770 (ft
60 (min/h) / 13.5 (ft
4.4 Thermal Load and Cooling Capacities
Calculation method
- i
3
) on the air conditioner coil
2
)  Flow rate/Specific volume
- i
1 3
3
3
/kg)
3
3
/lb)
) / (i - i ).
2 1 2
/min) 
/min) 
47